The left end of a long glass rod 8.00 cm in diameter, with an index of refractio

Question

The left end of a long glass rod 8.00 cm in diameter, with an index of refraction 1.60, is ground to a concave hemispherical surface with radius 4.00 cm. An object in the form of an arrow 1.50 mm tall, at right angles to the axis of the rod, is located on the axis 25.0 cm to the left of the vertex of the concave surface. A. Find the position of the image of the arrow formed by paraxial rays incident on the concave surface. B. Find the height of the image of the arrow formed by paraxial rays incident on the concave surface. C. Is the image erect or inverted?

Explanation / Answer

1/25.0 +1.6/s' = (1.6-1)/4

s' = 40cm (agreed)


Magntifcation = image height/object height = image distance/object diatance = s'/s
y'/1.5 = 40/25
y' = 2.4mm

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