For the transverse wave with displacement y=8m sin(2 pi/1m x + 4 pi/1s t) what i
ID: 2309001 • Letter: F
Question
For the transverse wave with displacement y=8m sin(2 pi/1m x + 4 pi/1s t) what is the wavespeed in meters/second? For the transverse wave with displacement y=8m sin(2 pi/1m x + 4 pi/1s t) what is the magnitude of the largest transverse velocity in meters/second? For the transverse wave with displacement y=8m sin(2 pi/1m x + 4 pi/1s t) what is the magnitude of the displacement at x=0.5m and time t=0.5s in meters? For the transverse wiive with displacement y=8m sin(2 pi/1m x + 4 pi/1s t) with tension 2N, what is the linear mass density, mu, in kilograms/meter? Two waves of amplitude lm that are equal in every way have a phase difference (relative phase) of pi/3 radians, what is the amplitude of the superposition of the two waves in meters? A string has two ends 2 meters apart that are fixed, it's tension is 5 Newtons, it's mass density is 3grams/meter what is the frequency (in Hertz) that corresponds to the largest wavelength?Explanation / Answer
a)
Compare the given wave equation with
Y=ASin(Kx-Wt)
Amplitude A=8 m
Wave number K=2pi
Since K=2pi/lambda
=>lambda =2pi/2pi =1 m
angular frequency W=4pi rad/s
since f=W/2pi =4pi/2pi =2 Hz
Wave speed
V=f*lambda =2*1 =2 m/s
b)
Maximum transverse velocity
Vmax=AW =8*4pi
Vmax = 100.53 m/s
c)
Y=8Sin(2pi*0.5+4pi*0.5)
Y=0 m
d)
Since
V=sqrt[T/u]
Linear mass density
u=T/V2 = 2/22 =0.5 kg/m
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