For the test circuit shown in Figure 1, calculate how the source voltage vs(t) s

Question

For the test circuit shown in Figure 1, calculate how the source voltage vs(t) should divide between resistors R1 and R2, i.e., calculate v1(t) and v2(t) in terms of vs(t), given R1 = 3.3 kOhm and R 2 = 4.7 kOhm. Note: Ohm's Law, Kirchhoff s Current Law (KCL), and Voltage (KVL) Law apply to time-varying signals. Therefore, the voltage division rule still applies.

Explanation / Answer

in the xircuit is=Vs/(Rs+R1R2) =>V1=isR1=VsR1/(Rs+R1+R2) =3.3vs/(3.3+4.7+.05) =.41Vs =>V2=isR2=VsR2/(R2+R1+Rs)=4.7Vs/(4.7+3.3+.05)=.584Vs =>Vin=Vs-isRs=Vs-VsRs/(R1+R2+Rs)=.995Vs VRs=.005Vs

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