A converging lens has a focal length of 19.2 cm. Give the image distance and mag

Question

A converging lens has a focal length of 19.2 cm. Give the image distance and magnification for the following object distances, using the correct sign conventions. Select all options that correctly describe the image. If the image is located at infinity, enter "infinity" for the image distance and for the magnification, and select "no image is formed".

(a) object distance = 39.5 cm (b) object distance = 19.2 cm (c) object distance = 10.4 cm
FInd image distance for each?
cm
Find magnification for each?
X

Which ones apply for each? (select all that apply)

upright

same side of lens as the object

virtual

side of lens opposite the object

real

inverted

no image is formed

Explanation / Answer

1/di + 1/d0 = 1/f

Magnification = -di / d0

object distance = 39.5 cm

1/di = 1/f – 1/d0 = 1/19.2 – 1/39.5

di = 37.36 cm

Magnification = -di/d0 = 37.36 / 39.5 = - 0.946

---------------------------------------------------

1/di + 1/d0 = 1/f

object distance = 19.2 cm

1/di = 1/f – 1/d0 = 1/19.2 – 1/19.2 = 0

---------------------------------------------------

1/di + 1/d0 = 1/f

object distance = 10.4 cm

1/di = 1/f – 1/d0 = 1/19.2 – 1/10.4

di = -22.69 cm

Magnification = -di/d0 = 22.69 / 10.4 = 2.18

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