UALR (just outside the Physics Building): Latitude = 34° 43’ 10.5’’ Longitude =

Question

UALR (just outside the Physics Building): Latitude = 34° 43’ 10.5’’ Longitude = 92° 20’ 39.0’’ Intersection of I40 and I430: Latitude = 34° 49’ 08.2’’ Longitude = 92° 20’ 39.0’’ Distance between the two points = 11.1 km

Size of the Earth: UALR latitude as a decimal number: 34.72deg (Show calculation.)

Intersection of I40 and I430 latitude as a decimal number: 34.82 deg (Show calculation.)

Intersection of I40 and I430 latitude minus UALR latitude: 0.1 deg (Show calculation.)

Circumference of Earth (round to nearest km): __________ km (Show calculation.) and then (Explain clearly in words the concepts behind the calculation.)

Radius of the Earth (round to nearest km): __________ km (Show calculation.)

Percent error (Express as a percentage, one decimal place): __________ % (Show calculation.)

Record and/or calculate the following (round to one decimal place): Proportional diameter of the Moon: __________ cm

Proportional diameter of the Earth: __________ cm

Ratio of (Proportional Diameter of Earth)/(Proportional Diameter of Moon): ________ (Show calculation.)

Explanation / Answer

convert 43'10.5" to degree

1 degree = 60'

10.5"= 10.5/60 ' = 0.175 '

43.175' = 43.175/60=0.719 or 0.72 deg

so 34° 43’ 10.5’’= 34.72 degree

similarly 34° 49’ 08.2’’ = 34 + ( 49 +(08.2/60))/60 = 34.82 degree

difference in latitude = 34.82-34.72=0.1 degree

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