1.) A coil consists of 450 turns of wire and has a total resistance of 2.00 ohm.
ID: 2306060 • Letter: 1
Question
1.) A coil consists of 450 turns of wire and has a total resistance of 2.00 ohm. Each turn is squared 18.0 cm sideways and a uniform magnetic field is activated perpendicular to the plane of the coil. If the field changes linearly from 0.000 to 0.500 T in 0.120 S. What is the magnitude of the induced voltage in the coil while the field is changing? 2.) A loop with an area of 0300 m 2 is immersed in a fluctuating field perpendicular to this. If the induced voltage measured during 10.0 s is 10.0 V, determine the change in the magnetic field flow and the change in the magnetic field during that time. 3.)3. A circular loop with a radius of 0.100 m is immersed in a magnetic field of 7.50 t perpendicular to this. If the field is linearly reduced to 2.50 T in 10.0 s, determine the induced voltage in the loop. If the loop has a total resistance of 2.00 ohm, determine the induced current. 4.) 4. In a rectangular loop with dimensions 4.00 cm x 5.00 cm A current of 2.00 x10 A (-3) A is observed during a time interval of 2.00 s. During this interval it was observed that the magnetic field, perpendicular to the loop, changed. If the total bond strength is 5.00 ohm, determine the magnetic field changeExplanation / Answer
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1.
Area of each coil
A=0.182 =0.0324 m2
Induced Voltage in the coil is given by
E=NAdB/dt =450*0.0324*(0.5-0)/0.12
E=60.75 Volts
2.
Induced Voltage in the loop is given by
E=NAdB/dt
10 =1*0.3*dB/10
dB =333.33 T
If it A=300 m2
=>10 =1*300*(dB/10)
dB=0.3333 T
3.
Induced emf
|E|=NA|dB/dt| =1*(pi*0.12)*|2.5-7.5/10|
|E|=0.0157 V
Induced current
I=0.0157/2 =7.854*10-3 A or 7.854 mA
4.
Induced emf
E=IR =2*10-3*5 =0.01 V
since E=NAdB/dt
0.01=1*(0.04*0.05)*dB/2
dB=10 T
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