1.) A 0.50 k g bullfrog is sitting at rest on a level log. How large is the norm

Question

1.) A 0.50kg  bullfrog is sitting at rest on a level log. How large is the normal force of the log on the bullfrog? Express your answer using two significant figures.


2.) A second 0.50kg bullfrog is on a log tilted 38? above horizontal. How large is the normal force of the log on this bullfrog? 1.) A 0.50kg  bullfrog is sitting at rest on a level log. How large is the normal force of the log on the bullfrog? Express your answer using two significant figures.


2.) A second 0.50kg bullfrog is on a log tilted 38? above horizontal. How large is the normal force of the log on this bullfrog?

Explanation / Answer

1.) Normal force = mg = 0.5*9.8 = 4.90 N

2.) Normal force = mg*cos(38) = 4.90 * cos(38) = 3.86 N

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