Wlles the same resistivity l have D) The longer wire has 3/4 times the resistivi
ID: 2305426 • Letter: W
Question
Wlles the same resistivity l have D) The longer wire has 3/4 times the resistivity of the shorter wire. Problem 9 (5 pts): Consid passing throughR () and the curr er the circuit shown in the figure. When the switch S is closed, how will the current ent passing through the battery ) change? switch A) Vi will increase, Ir will increase. I, will remain the same, Ir will increase. C) I, will decrease, Ir will increase D) 1I will decrease, Ir will decrease. E) I, will remain the same, Ir will decrease. Problem 10 (5 pts): A resistor and a capacitor are connected in series across an ideal battery having a constant across the resistor is batery,t fe soisacet tis made with the battery, the voltage vouos the rosisfur iscontat i.made withExplanation / Answer
Answer for Problem 9
When switch S is closed current I1 will remain same but current IT will increase.
Option B is correct answer.
Explaination:
As soon as the switch S is closed the resistance of the circuit will decrease because now three resistaces are in parallel to each other instead of two ( when switch was open)
As the resistance of the circuit decreases the total current drawn from the cell will increase. Hence IT will increaes. This can be explained using Omm's law
Current = V/R . Since V is constant therefore if R decreases then current will increase.
Since potential difference across each resistance is same and equal to potential difference of terminals or cell in parallel so it does not matter how many resitances are in parallel but current from each resistance is same as previous (when switch was open) because current = V/R hence Current in R1 is I1 = V/R1 here even switch is open or closed the value of V and R1 is same therefore the current from R1 means current I1 remains the same although total current increases but this total current will be divided into three parts now as then third resistance is also in circuit when the switch is closed.
Answer for Problem 10
When A resistor and capacitor are connected in series across idael battery and at the moment contact is made with the battery, the capacitor is not charged and it just acts as a path for current at t = 0 and maximum current passes through resiatnce at this moment. Therefore at the moment contact is made with battery, the voltage across the resistor is same as voltage of the battery. As soon as current starts flowing the capacitor gets charged and current in the circuit goes decreasing while charging the capacitor and hence potential equation can be written as E = I R + q/c where IR is the potential difference across resistor and q / C is potential across capacitor. But at t = 0 when contact is made with battery since there is no charge on capacitor hence q = 0 therefore from equation E = IR so the voltage across Resistor is same as voltage across the terminals of the battery.
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