Suppose an electron is accelerated from rest through a potential difference of 2

Question

Suppose an electron is accelerated from rest through a potential difference of 25kV. It encounters a magnetic field at right angles to its direction. A proton is then accelerated with that same potential and enters the same field at right angles with it. Assume the field is 1.0 T for both cases. Calculate the radii of the circular orbit both will make once trapped in this field and determine the ratio rp/re (proton radius and electron radius ratio).

A) 46 B) 122 C) 5 D) 2

Please help me solve this problem, Im lost.

Explanation / Answer

A) 46

r=mv/bq

rp/re=mpvp/meve.....as B and q are same for both

but velocity=sqrt(2qV/m).....V is potential diff

therefore rp/re=sqrt(mp/me).....by substituting the velocity formula as abave

implies

rp/re=46

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