Show work detail. You have two containers of a monatomic ideal gas that are inti

Question

Show work detail. You have two containers of a monatomic ideal gas that are intially at the same Pressure, Volume, and Temperature.

You add 560 J of heat to container 1 in a constant temperature process.

You add 560 J of heat to container 2 in a constant pressure process.

What is the difference in work done in these processes, 1 - 2? In other words, if W1 is the work done in process 1 and W2 is the work done in process 2, what is W1 - W2?

Give you answer in Joules to three significant digits. Do not include units with your answer.

Explanation / Answer

Work of container under constant temperature:

Q1 = W1 so if Q1 = 560 J, then W1 = 560 J.

Work of container under constant pressure:

Q2 = (5/2)P?V

W2 = P?V

If Q2 = 560 = (5/2)P?V, then P?V = 224J = W2

W1 - W2 = 336J

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