A 6.64 x 10-27 kg mass particle with positive 3.2 x 10-19 C charge is initially

Question

A 6.64 x 10-27 kg mass particle with positive 3.2 x 10-19 C charge is initially moving parallel to the wire with a 110 m/s speed when it is at point P, as shown below. With reference to the coordinate system established above, what is the direction of the magnetic force acting on the positive particle at point P? in the negative y-axis in the positive y-axis in the positive z-axis in the negative x-axis in the positive x-axis An electric field is applied that causes the net force 011 the positive particle to be zero at point P. With reference to the coordinate system established above, what is the direction of the electric field at point P that could accomplish this? in the negative y-axis in the negative x-axis in the positive x-axis in the negative z-axis in the positive y-axis in the positive z-axis

Explanation / Answer

The answer to part 1 is (1) negative y-axis.

This is because the current in the wire is moving to the left, in the negative x direction. This means, according to the right-hand rule, that the magnetic field circles the wire coming out of the paper below the wire and going into the paper above the wire; in other words, at point P the magnetic field is pointing in the negative z direction.

Therefore the magnetic force on the particle, which is calculated as the cross product v X B, must point in the direction your thumb takes when you sweep the fingers of your right hand from the particle velocity vector into the magnetic field vector. Which is down, negative y.

And thus the answer to part 2 is positive y, the electric field to counteract must point straight up.

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