PLEASE HELP!!! ONLY PART B, C, D PART A An object 1.4 cm high is placed 18.7 cm

Question

PLEASE HELP!!! ONLY PART B, C, D

PART A

An object 1.4 cm high is placed 18.7 cm to the left of a converging lens of focal length 11.2 cm. Find the position of the image of this object relative to this lens. Use a positive sign if the image lies to the right of the lens, and vice-versa.

ANSWER = 27.9 cm

PART B

A second converging lens of focal length 19.3 cm is placed 50 cm to the right of the first lens. The image produced by the first lens now becomes the object for the second lens. Find this object distance, ie the distance between the first image and lens 2. Use a positive sign if the position is to the left of lens 2, and vice-versa.

PART C

How far from the second lens is the image that it forms? The value should be positive if the image lies

to the right of lens 2, and vice-versa.

PART D

What is the height of the final image? Use a positive sign if it is upright, and vice-versa.

Explanation / Answer

A) first lens

1/S1 +1/S1' = 1/F

1/18.7 + 1/S1' = 1/11.2

S1' = 27.9 cm

B)

S2 = 50 - 27.9 = 22.1 cm

C) 1/22.1 + 1/S2' = 1/19.3

S2' = 152.33..from the second lens

S2' = +152.33..from the second lens

D )M = (-S1'/S1)*(-S2'/S2) = (-27.9/18.7)*(-152.33/22.1) = 10.28

M = image / object

image = M*object = 14.4 cm

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