While you are operating the Turkish Twist ride at the local amusement park you s

Question

While you are operating the Turkish Twist ride at the local amusement park you spot a passenger who ate too much cotton candy and is regretting getting on the ride.

You decrease the angular speed of the cylinder from 4:0 rad/s to 2:0 rad/s in 20:0 revoluations at constant angular acceleration.

(a) What is the angular acceleration during this decrease?

(b) How much time did this speed decrease take?

(c) If the ride has a diameter of 5 meters, what speed will the rider be travelling at after the decrease in speed is complete?

Explanation / Answer

a)
V^2=u^2+2*a*s
s=20 revolution
=20*2*pi
=125.66 rad

V^2=u^2+2*a*s
2^2=4^2+2*a*125.66
a= -0.0477 rad/sec

b)
V=u+at
2=4 -0.0477t
t=41.93 sec

c)
V=r*w
V=2.5*2
= 5 m/s

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