A tank whose bottom is a mirror is filled with water to a depth of 19.6cm . A sm

ID: 2298218 • Letter: A

Question

A tank whose bottom is a mirror is filled with water to a depth of 19.6cm . A small fish floats motionless 7.30cm under the surface of the water.

What is the apparent depth of the fish when viewed at normal incidence to the water?

Express your answer in centimeters. Use 1.33 for the index of refraction of water.

What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?

Express your answer in centimeters. Use 1.33 for the index of refraction of water.

Given that

H1 = 20.2 cm

H2 = 7.30 cm

n = 1.33

(a) the apparent depth of the fish when viewed at normal incidence to the water is

d1 = H2 / 1.33

= 7.30 cm / 1.33

= 5.48 cm

(b) The apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence is

d2 = (2H1 - H2 ) / 1.33

= (2 x 20.2 cm - 7.30 cm) / 1.33

= 24.88 cm

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