consider an arrangement of converging and diverging lenses as shown below and an

ID: 2298158 • Letter: C

Question

consider an arrangement of converging and diverging lenses as shown below and answer the four questions at the end!

A) if the concave lens were not there, where would the image for the convex lens be located (relative to that lens)

B) Where is the image due to the concave lens located (relative to the concave lens-assume the convex lens isnt there)

C) Relative to the convex lens where is the final image located for this system of lenses? Is the image real or virtual? is it up right or inverted?

D) What is the total magnification for this system? Is the image magnified?

A)
1/S1 +1/S1' = 1/F

1/36 + 1/S1' = 1/12

S1' = (36*12)/(36-12) = 18 cm

B )

1/66 + 1/S2' = -1/6

S2' = -5.5cm

C)
1/S3 + 1/S3' = 1/F

1/(30-18) + 1/S' = -1/6

S3' = -4 cm to the left of concave lens

d = 30-4 = 26 cm to the righ ot convex lens (in between them)

virtual , upright

D) M = m1*m2 = (-S1'/S1)*(-S3'/S3) = (-18/36)*(4/12) = -0.167

M < 1.....not magnified

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.