please show me all works thank you so much In one nuclear reactor reaction, a 92
ID: 2296330 • Letter: P
Question
please show me all works thank you so much
Explanation / Answer
The nuclear reaction is
(235,92)U = (92,37)Rb +(140,55)Cs +3*(1,0)n + energy
atomic masses are
M(235U) =235.0439 amu
(http://en.wikipedia.org/wiki/Uranium-235)
M(92Rb) =91.9197 amu
(http://en.wikipedia.org/wiki/Isotopes_of_rubidium)
M(140Cs) =139.9173 amu
(http://en.wikipedia.org/wiki/Isotopes_of_caesium)
M(1n) =1.00866 amu
mass defect is
Delta(M)= 235.0439 - 91.9197 -139.9173 -3*1.00866 =0.18092 amu
(E = m*c^2)
1 amu = 1.6605*10^-27 kg = 931.5 MeV =1.4904*10^-10 J
Energy released is by a single (235,92)U atom
E = 0.18092*931.5 =168.527 MeV = 2.69*10^-11 J
For hydrogen the energy of combustion is
E(H) = 286 KJ/mol =286*10^3/6.022*10^23 =4.75*10^-19 J
(http://en.wikipedia.org/wiki/Heat_of_combustion#Heat_of_combustion_tables)
The energy released in the fission reaction is 8 orders of magnitude higher!
A cup of water mas mass m =200 g.
Caloric capacity of water is c=4.18 J/g/K
Heat needed to increse temperature of water from 300 K to 373 K is
Q =200*4.18*(373-300) =61028 J
Number of fissions is
N = Q/E =61028/2.69*10^-11 =2.27*10^15 atoms
One mole of 235U has mass M =235 g
The mass of U is
m = M*N/Na =235*2.27*10^15/6.023*10^23 =8.85*10^-7 grams! = 8.85*10^-10 kg of U
Na is Avogadro number.
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