please help and show work! thanks Assume that a certain location on the Earth re

Question

please help and show work! thanks

Assume that a certain location on the Earth reflects 36.0% of the incident sunlight from its clouds and surface. (a) If the intensity of solar radiation is 1415 w/m2, what is the radiation pressure (Prad) o n the Earth at this location? 14e-3 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Pa (b) Compare this to normal atmospheric pressure (Pa) at the Earth's surface, which is 101 kPa. Prad is Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. times smaller than atmospheric pressure.

Explanation / Answer

radiation pressure is given by:

intensity / c for absorbed light and

2 * intensity / c for reflected light.

In this problem, 36% of the light is reflected and 64% is absorbed. So you have

    reflected intensity = 0.36 * 1415 = 509.4

    absorbed intensity = 0.64 * 1415 =   905.6

Then...

pressure from reflected light = 2 * 509.4 / 3 x 10^8 =  3.396 x 10^-6 Pa

pressure from absorbed light = 905.6 / 3 x 10^8   = 3.01 x 10^-6 Pa

Total pressure = (3.396+3.01) x 10^-6 =    6.406 x 10^-6 Pa

b)

Prad / Pa = 6.406 * 10^-6 / 101000 = 6.342 * 10^-11

So, P rad is smaller than Pa....

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