%3Cp%3E1.%20an%20electron%20is%20released%20at%20point%20a%20where%20the%20elect
ID: 2294894 • Letter: #
Question
%3Cp%3E1.%20an%20electron%20is%20released%20at%20point%20a%20where%20the%20electric%0Apotential%20is%20measured%20as%204v.%20when%20the%20electron%20reaches%20point%20b%2C%0Awhere%20the%20electric%20potential%20is%20measured%20as%2024v%2C%20its%20speed%20is%0A3.5x10%5E6%20m%2Fs.%20what%20was%20the%20electrons%20speed%20at%20point%20a%3F%3C%2Fp%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3Eanswer%20is%202.2910%5E6%20m%2Fs%20please%20explain%20why!%3C%2Fp%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3E2.%20A%20certain%20capacitor%20has%20a%20capacitance%20of%203.0%20uF.%20While%20it%20is%0Acharge%20dto%203.0%20uC%20and%20isolated%2C%20the%20plates%20are%20pulled%20apart%20so%20its%0Acapacitance%20becomes%201.0%20uF.%20The%20work%20done%20by%20the%20pulling%20agent%20is%0Aabout%3A%3C%2Fp%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3Eanswer%20is%203.0x10%5E-6%20J.%20Why%20is%20this%3F%3F%3F%3C%2Fp%3E%0AExplanation / Answer
force on electron= qV
with the variation of voltage force(acclration * mass ) varies which causes change in speed.
V = u+ at
2::::
energy stored in capacitor = 1/2 C V^2
work done = change in enrgy stored(calcualte initial enrgy and final enrgy)
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