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iPad Notes February 19, 2014, 2:17 PM Consider a typical 1500 - kg automobile going up a steep (say, 10 degrees from horizontal) stretch of freeway. At 60 mph, the car goes one mile in one minute and increases its altitude by 0.17 miles, or about 300 meters. By how much does the gravitational potential energy of the car increase during this one minute? What must the (minimum) power output of the car's engine be, in Watts? In horsepower? By what factor would the required engine power output change if we were talking about a loaded truck (with a 10x greater mass, 15,000 kg) instead of a car?Explanation / Answer
Part A)
PE = mgh
PE = (1500)(9.8)(300)
PE = 4.41 X 10^6 J
Part B)
P = Energy/t
P = 4.41 X 10^6/60
P = 7.35 x 10^4 W
Divide by 746 for the conversion to hp
7.35 X 10^4/746 = 98.5 hp
Part C)
Since everything is directly proportional to mass, the power output would be 10 times greater
Thus 10x
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