SCN 3+ FeSCN2 (calculate the initial and equilibrium) (read the equilibrium valu
ID: 229446 • Letter: S
Question
SCN 3+ FeSCN2 (calculate the initial and equilibrium) (read the equilibrium value from the Microlab table) Solution 1 2.00x10A-4 1.00x10A30 Initial Change Equilibrium Solution 2 (2.00x10-4)-x --(1.00 10·3)--10+x 1.59x10A-4 I Kc = 269 9.59x10A-4 4.097x10A-5 Initial Change 4.00x10A4 1.00x104-3 0 K, = 294 Equilibrium 3.15x10A-4 9.15x104-4 8.478x10A-5 Solution 3 1.00x10A 3 Initial Change Equilibrium14.80x10n4 Solution 4 6.00x10A-4 0 (6.00x10A-4)-x (1.00x104-3)x 0+x K. 285 | 8.80x10^-4-1-1.204-1 0A-4 Initial Change Equilibrium Solution 5 8.00x10A-4 1.00x10A-3 0 (8.00x10^-4)-x | (1.00x10^-3)-x-10+x 6.88x104-4 8.88x104-4 Kc = 183 1.119x10A-4 Initial Change Equilibrium 8.24x10n-4 8.24x10 1.00x104-3 | (1.00x10^-3)-x 10.0x10A-4 0 | 0+x 4 1.762x10-4 (10.0x10-4)-x K = 260Explanation / Answer
Answer (1): Kc values should be same or atleast similar for different solutions having different initial concentrations. This is because equilibrium constant depends on the temperature not on the concentrations of reagents. So if we performed above experiment at same temperature then the Kc values should be same. According to "Le chatelier's principle" changing the concentration only changes the position of equilibrium, means that suppose any reaction is in equilibrium and we added some more reactant then at that time equilibrium will get disturbed so to again retain equilibrium reaction will move forward to compensate the added amount.
Answer (2): As we talked in above question that Kc values should be similar, here we can see almost all Kc values are in approx. same range (except for the Solution 4). The differences in these values may rise due to experimental errors. It may be possible that concentrations were not measured accurately, there may be some error while measuring the absorbance etc.
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