I need a code for matlab to solve this problem 6.16 A three-phase tranmission li

Question

I need a code for matlab to solve this problem

6.16 A three-phase tranmission line is 300 mi long and serves a load of 400 MVA 0.8 lagging power factor at 345 kV. Te ABCD constants of the line are A D 0.8180/13 C0.001933/904 S (a) Determine the sending-end line-to-neutral voltage, the sending end current and the percent voltage drop at full load. (b) Determine the receiving-end line-to-neutral voltage at no load, the sending end current at no load and the voltage regulation. Solution 400,000 x 345 001141-MAT A Vs 08180213e x199, 18620° +172.24 84 2, x 669 44-36 Er 256,738/20152v Is0001933 904 x 199,1860+08180936 3 4/-36 87 447.72 85A A Voltage drop256, 738-199, 186 x100 22.4 % 256, 738 256.738 VR. NL 313,861 L 1885-V 3138614 = 0.8180 /1.3 IS, NL 0.001933/904°× 313. 86148 85??606 7110925 313.861-199.186 = 57.6% %Reg. 199, 186

Explanation / Answer

clc;clear;
%Z = R.*exp(i*theta)
P = 345e3*exp(i*0);
P_load =400e6*exp(-i*pi*(acos(0.8)*180/pi/180));
A = 0.8180*exp(i*pi*(1.3/180));
D = 0.8180*exp(i*pi*(1.3/180));
B = 172.2*exp(i*pi*(84.2/180));
C = 0.001933*exp(i*pi*(90.4/180));
Vr = P/sqrt(3);
Ir = P_load /(sqrt(3)*P);
% -----------------------------

Vs = A * Vr + B * Ir;

Is = C * Vr + A * Ir;

Voltage_Drop = (abs(Vs) - abs(Vr))/abs(Vs)*100
% ----------------------------

Vr_NL = Vs / A ;
Is_NL = C * Vr_NL ;

% -------------------

Per_Regulaation = (abs(Vr_NL) - abs(Vr))/abs(Vr)*100

-----------------------------------------------------------

Result:

Command Window:

Voltage_Drop =

22.4161

Per_Regulaation =

57.5706

>>

---------------------------------

to check absolute value and angle use following command

i.e to check Vr_NL in phasor form

abs(Vr_NL) and angle(Vr_NL)*180/pi

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