1.Vector \"A\" has magnitude 300 grams and creates angle of +30 degrees with pos
ID: 2290719 • Letter: 1
Question
1.Vector "A" has magnitude 300 grams and creates angle of +30 degrees with positive x-axis. Vector "B" has magnitude 400 grams and create angle of +30 degrees with positive y-axis. What is magnitude and direction of vector "C" which is the vector product of ("A" x "B")
When the scalar product of two vectors is minimum when the angles between two vectors is how many degrees?
when the scalar product of two vectors is zero when the angle betweemn two vectors is how many degrees?
Vector A = sqrt(3)i while vector B = j. What is magnitude and direction of vector C = A - B?
1.Vector "A" has magnitude 300 grams and creates angle of +30 degrees with positive x-axis. Vector "B" has magnitude 400 grams and create angle of +30 degrees with positive y-axis. What is magnitude and direction of vector "C" which is the vector product of ("A" x "B")
When the scalar product of two vectors is minimum when the angles between two vectors is how many degrees?
when the scalar product of two vectors is zero when the angle betweemn two vectors is how many degrees?
Vector A = sqrt(3)i while vector B = j. What is magnitude and direction of vector C = A - B?
Explanation / Answer
1.) So angle bwtween A and B is 90 degrees
A x B = |A||B|sin(theta) = |A||B|sin(90) = |A||B| = 300*400 = 120000
Direction is towards positive z axis.
2.) a.b = |a||b|cos(theta)
so a.b is minimum when theta = 180 degrees
3.) a.b = 0 means cos(theta) = 0
So theta = 90 degrees
4.) C = A - B = sqrt(3)i - j
Magnitude = sqrt(3+1) = sqrt(4) = 2
Direction = tan^(-1) = (-1/sqrt(3)) = -30 degrees = 330 degrees with positive x axis
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