1.Two parallel conducting plates are separated by 10.0 cm, and one of them is ta
ID: 1397417 • Letter: 1
Question
1.Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts.
(a) What is the electric field strength between them, if the potential 9.00 cm from the zero volt plate (and 1.00 cm from the other) is 510 V?
kV/m
ONLY NEED b
2.In the diagram below, each division on the horizontal axis is 0.20 m while each division on the vertical axis is 1.5 V. What is the electric field in each of the regions specified below?
(a) from 0.0 m to 0.30 m
0 V/m
(b) from 0.30 m to 0.70 m
????? V/m
(c) from 0.70 m to 0.80 m
0 V/m
Explanation / Answer
1) In order to solve for the electric field we have to understand very key relationship between electric field and electric potential.
Electric potential =V = E.d
E = V / d = 510Volt / 9cm = 0.56 Volt / m
Part b
As we know that the electric field is the negative gradient of electric potential.
b)E = - dV / dr
E = - ( V2-V1) /( r2 - r1)
E = - (3.5 -4.5) / (0.70 - 0.30)
E = - (-1) / 0.4
E = 2.5 Volt / meter
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.