Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

We have a phosphoresent tube with a potential difference between the two ends. I

ID: 2290646 • Letter: W

Question

We have a phosphoresent tube with a potential difference between the two ends. It has allowed the gas inside to ionize. There are He+2 and He+1ions present as well as electrons. Imagine that the ions are moving to the left at the same time that some electrons are moving to the right past the same location.

Part A

Will the net current be to the right, to the left, zero, or none of the preceding?

Will the net current be to the right, to the left, zero, or none of the preceding?

SubmitMy AnswersGive Up

Part B

In 4.69s , 5.84C of electrons flow to the right at the same time that 8.5C of He+1 flow to the left. What are the direction of the current due to the ions?

In 4.69 , 5.84 of electrons flow to the right at the same time that 8.5 of  flow to the left. What are the direction of the current due to the ions?

SubmitMy AnswersGive Up

Part C

What are the magnitude of the current due to the ions?

SubmitMy AnswersGive Up

Part D

What are the direction of the current due to the electrons?

What are the direction of the current due to the electrons?

SubmitMy AnswersGive Up

Part E

What are the magnitude of the current due to the electrons?

SubmitMy AnswersGive Up

Part F

What are the direction of the total current?

What are the direction of the total current?

SubmitMy AnswersGive Up

Part G

What are the magnitude of the total current?

SubmitMy AnswersGive Up

Part H

Now assume the He+2 ions move to the right at a rate of 1.63

to the right to the left zero none of the preceding

Explanation / Answer

part a)

current is towards left because direction of current due to both + and - is towards left

part b)

direction of current is towars the motion of +ve ions, that is towards left

part c)

I1=q/t=8.5/4.9

part d)

direction of current due to electrons will be opposite to teh direction of motion , so it is towards left

part e)

I2=q/t=5.84/4.59

part f)

direction of total current=left

part g)

magnitude=I1+I2

part h)

net current=(3.68-1.63)1018

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote