the RDA of sodium is 1. One snack food packaging contains 37 grams of dried vege

Question

the RDA of sodium is 1. One snack food packaging contains 37 grams of dried vegetable. The student takes the entire contents of the package and grinds it using pestle and mortar. After the sample is prepared, the student takes exactly 1.00 grams of sample and dissolves it in adequate volume of water. She then adds 5 drops of indicator and titrates to the end-point using 0.100 M AgNOs solution. The volume of AgNOs needed for titration is 10.50 mL. a. What is the amount of salt in the package? b. The RDA of sodium is 904 mg. What is the percent RDA of sodium intake if a person eats the content of the package? Na 23

Explanation / Answer

Moles of AgNO3 consumed during titration for 1 gram of sample = molarity * volume used

= .100 * 10.50*10-3

= 0.00105 moles

Now, while titrating 1 mole AgNO3 is consumed by 1 mole of NaCl.

therefore moles of Na+ in 1 gram of sample = 0.00105

moles of Na+ in 37 gram of sanck food = 0.03885

weight of Na+ in 37 gram of snack food = 0.03885 moles * 23 gram/moles

= 0.89355 grams

= 893.55 mg

According To Question

RDA of Sodium = 904 mg

% RDA of sodium intake if a person eats the content of the package = 893.55/904 *100

=98.844

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