The net force on charge 3 is I am pretty sure its NOT zero... Two charged partic

Question

The net force on charge 3 is

I am pretty sure its NOT zero...

Two charged particles, with charges qq and q24q, are located at a distance d- 2 cm apart on the x axis. A third charged particle, with charge q3, is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3. Find the position of charge 3 when q = 2.0nC Note that you are given the magnitude of q, but the sign of the charge q is not specified. q can be positive or negative, so that the three charges (g1 42, 3) are either all positive charges or all negative charges

Explanation / Answer

since q1,q2 are +charegs

so when q3 lies in between the charegs, then force on q3 due to q1 and q2 will be in opposite direction, irrespective of weather q3 is -ve or +ve

net force

Fa=|F1-F2|=2 N

in this case we are assuming q3 is right of q1 and q2 is right of q3

when we put q3 to he left of q1

then distance of q3 fromq1 will remain same

but it will increase in teh case of q2,so force F2n will decrease than F2

at this point both the forces are in same direction

so net force Fb=|F1+F2n|

comparing Fa and Fb

Fb will increase

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