1.) An electron with an initial speed of 700,000 m/s is brought to rest by an el

Q: 1.) An electron with an initial speed of 700,000 m/s is brought to rest by an el

1 a. As we know dat Energy = Ve ie 0.5mv^2 = Ve we know dat m = 1.67 * 10^-27 kg and e = 1.6 *10^-19 C hence V = 0.5* 1.67* 10^-27 * (700,000)^2/(1.6 *10^-19) = 2557.19 V b . Again for the 2nd part we ve 0.5mv^2 = Ve hence KE will be same = 2557.19 eV

ID: 2288662 • Letter: 1

Question

1.) An electron with an initial speed of 700,000 m/s is brought to rest by an electric field.

a.) What was the potential difference that stopped the electron?

b.) What was the initial kinetic energy of the electron, in electron volts?

2.) A parallel-plate capacitor is constructed of two horizontal 13.6-cm-diameter circular plates.A 1.4g plastic bead, with a charge of -4.0nC is suspended between the two plates by the force of the electric field between them. What is the charge on the positive plate?

Explanation / Answer

1
a. As we know dat

Energy = Ve

ie 0.5mv^2 = Ve

we know dat

m = 1.67 * 10^-27 kg
and e = 1.6 *10^-19 C

hence V = 0.5* 1.67* 10^-27 * (700,000)^2/(1.6 *10^-19)

= 2557.19 V

b . Again for the 2nd part we ve

0.5mv^2 = Ve
hence

KE will be same = 2557.19 eV

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1.) An electron with an initial speed of 700,000 m/s is brought to rest by an el

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