q 2 = -6.16 micro C and mass 1.67g , is projected toward q 1. When the two spher

Question

q2 = -6.16microC and mass 1.67g , is projected toward q1. When the two spheres are 0.800 m apart, q2 is moving toward q1 with speed 22.0 m/s (Figure 1) . Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.

Part A

What is the speed of q2 when the spheres are 0.312m apart?

SubmitMy AnswersGive Up

Incorrect; Try Again; 19 attempts remaining

Part B

How close does q2 get to q1?

SubmitMy AnswersGive Up

Incorrect; Try Again; 19 attempts remaining

Explanation / Answer

since both charges are -ve, the force between them is repulsive

so as the distance between charges decreases, speed of q2 will decrease and eventually it will stop

part a)

F1=ma1=kq1q2/0.82

F2=ma2=kq1q2/0.3122

now v2-u2=2as

here u=22m/s,a=a2,s=0.8-0.312,v=v

so a2=(v2-u2)/2s

putting a2 in above equation

m(v2-u2)/2s=kq1q2/0.3122

v=(kq1q2(2s)/(m*0.3122)+u2)1/2

part b)

in the above equation ,putting v=0

value of s for v=0

is the closest distance

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.