A small metal sphere, carrying a net charge of q 1 = -3.27 micro C , is held in

Question

A small metal sphere, carrying a net charge of q1 = -3.27microC , is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2 = -6.16microC and mass 1.67g , is projected toward q1. When the two spheres are 0.800 m apart, q2 is moving toward q1 with speed 22.0 m/s (Figure 1) . Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.

Part A

What is the speed of q2 when the spheres are 0.312m apart?

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Part B

How close does q2 get to q1?

Explanation / Answer

since both charges are -ve, the force between them is repulsive

so as the distance between charges decreases, speed of q2 will decrease and eventually it will stop

part a)

F1=ma1=kq1q2/0.82

F2=ma2=kq1q2/0.3122

now v2-u2=2as

here u=22m/s,a=a2,s=0.8-0.312,v=v

so a2=(v2-u2)/2s

putting a2 in above equation

m(v2-u2)/2s=kq1q2/0.3122

v=(kq1q2(2s)/(m*0.3122)+u2)1/2

part b)

in the above equation ,putting v=0

value of s for v=0

is the closest distance

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