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A small mass M attached to a string slides in a circle (x) on a frictionless hor

ID: 2280626 • Letter: A

Question

A small mass M attached to a string slides in a circle (x) on a frictionless horizontal table, with the force F providing the necessary tension (see figure). The force is then increased slowly and then maintained constant when M travels around in circle (y). The radius of circle (x) is twice the radius of circle (y).


true, false, greater than, less than, equal to.

1. M's angular momentum at x is .... that at y.

2. M's angular velocity at y is four times that at x.

3. As M moves from x to y, the work done by F is .... 0.

4. While going from x to y, there is no torque on M

5. M's kinetic energy at y is four times that at x.

A small mass M attached to a string slides in a circle (x) on a frictionless horizontal table, with the force F providing the necessary tension (see figure). The force is then increased slowly and then maintained constant when M travels around in circle (y). The radius of circle (x) is twice the radius of circle (y). true, false, greater than, less than, equal to. M's angular momentum at x is .... that at y. M's angular velocity at y is four times that at x. As M moves from x to y, the work done by F is .... 0. While going from x to y, there is no torque on M M's kinetic energy at y is four times that at x.

Explanation / Answer

1) it is true,, becuase F = M x w1^2 and 2 F = M (x/2) w2^2 from which we see that w2 = 2w1

2) L1 = M x w1^2 and L2 = M (x/2) w2^ = 2 L1 , so it TWICE

3) true, since to torque is acting on it.

4) true

5) K1 = 1/2 M x^2 w1^2 and K2 = 1/2 M (x/2)^2 w2^2 so that we see that K2 = K1 , so it false.

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