General Chemistry 4th Edition . University Science Books presented by Sapling Le

Question

General Chemistry 4th Edition . University Science Books presented by Sapling Learning do | Map For the following reaction: CH30H(aq) H+(aq) CI-(aq) + CH,CI(aq) + H2O(1) 10-1- + 0 2.06 32.0 184 the value of [H'] was measured over a period of time. Given the data, find the average 660 172 119.0 1.55 rate of disappearance of H'(aq) for the time interval between each measurement Interval: 0 s to 32.0s 32.0 s to 66.0s 66.0 s to 119.0 s Number Number Number Reaction rate: M/ s M/ s What is the average rate of appearance of CHsCl(aq) for the same time intervals? 0s to 32.0s 32.0 s to 66.0s 66.0 s to 119.0 s Interval: Number Number Number Reaction rate: M/ s M/ s M/ s

Explanation / Answer

Average rate of disappearance of H+ = (initial concentration - final concentration)/(final time - initial time)


(a) From t = 0 s to 32.0 s

Rate = (2.06 - 1.84)/(32.0 - 0) = 0.006875 M/s = 6.88 x 10^(-3) M/s


(b) From t = 32.0 s to 66.0 s

Rate = (1.84 - 1.72)/(66.0 - 32.0) = 0.00353 M/s = 3.53 x 10^(-3) M/s


(c) From t = 66.0 s to 119.0 s

Rate = (1.72 - 1.55)/(119.0 - 66.0) = 0.00321 M/s = 3.21 x 10^(-3) M/s


CH3OH(aq) + H^+(aq) + Cl^-(aq) => CH3Cl(aq) + H2O(l)

1 mole of H+ gives 1 mole of CH3Cl

Average rate of appearance of CH3Cl = average rate of disappearance of H+


((a) From t = 0 s to 32.0 s

Rate = 0.006875 M/s = 6.88 x 10^(-3) M/s


(b) From t = 32.0 s to 66.0 s

Rate = 0.00353 M/s = 3.53 x 10^(-3) M/s


(c) From t = 66.0 s to 119.0 s

Rate = 0.00321 M/s = 3.21 x 10^(-3) M/s

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