show work please! Answer the following questions for the titration of SO 00 mL o
ID: 228590 • Letter: S
Question
show work please!
Explanation / Answer
mmoles of HA = 50 x 0.0200 = 1.0
0)
mmoles of HA = mmoleso f NaOH
1 = 0.100 x V
V = 10 mL
volume of NaOH needed = 10.00 mL
1)
pH = 1/2 (pKa - log C)
= 1/2 (6.27 - log 0.0200)
pH = 3.98
2)
mmoles of NaOH = 3 x 0.1 = 0.3
HA + NaOH -------------> NaA + H2O
1 0.3 0 0
0.7 0 0.3
pH = pKa + log [salt / acid]
= 6.27 + log [0.3 / 0.7]
pH = 5.90
3)
pH = pKa at half - equivalence point
pH = 6.27
4)
here salt reamains.
salt concentration = 1 / 50 + 10 = 0.0167 M
pH = 7 + 1/2 (pKa + log C)
= 7 + 1/2 (6.27 + log 0.0167)
pH = 9.25
5)
pH = 10.22
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