A point charge q 1=?4.00nC is at the point x =0.600 meters, y =0.800 meters, and

Question

A point charge q1=?4.00nC is at the point x=0.600 meters, y=0.800 meters, and a second point charge q2=+6.00nC is at the point x=0.600 meters, y=0.

Part A

Calculate the magnitude E of the net electric field at the origin due to these two point charges.

Express your answer in newtons per coulomb to three significant figures.

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Part B

What is the direction, relative to the negative x axis, of the net electric field at the origin due to these two point charges.

Express your answer in degrees to three significant figures.

A point charge q1=?4.00nC is at the point x=0.600 meters, y=0.800 meters, and a second point charge q2=+6.00nC is at the point x=0.600 meters, y=0.

Part A

Calculate the magnitude E of the net electric field at the origin due to these two point charges.

Express your answer in newtons per coulomb to three significant figures.

E =   N/C  

SubmitMy AnswersGive Up

Part B

What is the direction, relative to the negative x axis, of the net electric field at the origin due to these two point charges.

Express your answer in degrees to three significant figures.

? =   ? up from the negative x axis

Explanation / Answer

the magnitude E of the net electric field at the origin due to these two point charges.

E = kq/r^2

E = k*10-9( -4/1.02+ 6/0.62)

E = 114 N

2. the direction, relative to the negative x axis, of the net electric field at the origin due to these two point charges. = 48.18 degree above x- axis

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