%25253Cp%25253E%25253Cspan%252520style%25253D%252522font-family%25253A%252526nbs
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/ Answer
Energy stored in a capacitor is 0.5 * C * V^2.
Charge in a capacitor is C * V
Capacitance is eo * er * A / d
We can see that the difference in capacitance will be 6.7/1.00054 times the air capacitor.
The voltage difference will be 1.2E7 / 3E6.
Using the energy formula, we see that energy is proportional to capacitance and V^2.
So multiply the air cap's energy by the voltage difference squared times the capacitance difference.
You should end up with E = 0.041J * (1.2E7/3E6)^2 * (6.7/1.0054)
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