% mass A = mass of A/total mass middot 100 pV = nRT molarity = mol solute/kg sol
ID: 525154 • Letter: #
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% mass A = mass of A/total mass middot 100 pV = nRT molarity = mol solute/kg solvent molarity = mol solute/L solution X_A = mol A/total moles k_w = K_a moddot K_b = [OH^- I H^+] = 1.0 middot 10^-14 Delta H degree_exn = Sigma H degree_f (products) - Sigma H degree_f (reactants) (also for Delta G and Delta S) Delta G = Delta H - T Delta S Delta G = Delta G degree + RT In Q Delta S greaterthanorequalto Delta S + Delta S_surr S = k In W Delta S = q_ /T How might the conditions be changed so that the CO is more easily and efficiency produced?Explanation / Answer
Carbon monoxide has a molar mass of 28.0 (12+16=28)while on the other hand air is alightly heavier than carbon monoxide, which makes carrbon monooxide slightly less dense than air, whose average molar mass is 28.8. Now it important beacause, more is the pressure, higher is the production of carbon monooxide.
now reaction for the formation of CO,
2C + O2 = 2CO
condition for the formation of carbon monooxide,
1) incomplete combustion: incomplete combustion of any organic compound forms Carbon monooxide. Because if complete combustion will take place then CO2 , carbon dioxide is formed.
2) Supply of oxygen during reaction:
supply of oxygen should be low at the time of reaction for the formation of carbon monoxide, so incomplete combustion will take place in defeciency of oxygen.
3 Pressure: pressure should be a little high than atmospheric pressure.
4 Temperature: temperature should be from 80-1100C.
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