The drawing shows three particles far away from any other objects and located on

Question

The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles are mA = 327 kg, mB = 572 kg, and mC = 134 kg. Take the positive direction to be to the right. Find the net gravitational force, including sign, acting on (a) particle A, (b) particle B, and (c) particle C.

The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles are mA = 327 kg, mB = 572 kg, and mC = 134 kg. Take the positive direction to be to the right. Find the net gravitational force, including sign, acting on (a) particle A, (b) particle B, and (c) particle C.

Explanation / Answer

force on mass A is Fab+Fac

Fab=G*ma*mb/d^2=6.67*10^-11*327*572/(0.5^2)=0.000049 N

Fac=G*ma*mc/d^2=6.67*10^-11*327*134/0.75^2=5.19*10^-6N

Fnett=0.000049+0.00000519=0.00005419 N

on partical B is

Fab+Fbc=0.000049+6.67*10^-11*572*134/0.25^2=0.000049+0.0000817=0.00013N

on partical C

Fac+Fbc=5.19*10^-6+0.0000817=0.000086N

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