The drawing shows three point charges fixed in place. The charge at the coordina

Question

The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q1 = +7.20 µC; the other two charges have identical magnitudes, but opposite signs: q2 = -5.35 µC and q3 = +5.35 µC.

(a) Determine the net force (magnitude and direction) exerted on q1 by the other two charges.

magnitue_______ N

direction_______

(b )If q1 had a mass of 1.60 g and it were free to move, what would be its acceleration?

magnitude ______ m/s^2

direction ______

Explanation / Answer

Given that

q1 = +7.20*10^-6C

q2 = -5.35*10^-6C

and q3 = +5.35*10^-6C

a) The electric force on q1 due to q2 is given by

F2= k q1q2/r^2

= (9.0*10^9 N.m^2/C^2)(7.20*10^-6 C)(5.35*10^-6 C)/(1.30 m)^2

= 0.20513609467 N

The electric fore on q1 due to q3 is given by

F1 = k q1q2/r^2

=(9.0*10^9 N.m^2/C^2)(7.20*10^-6 C)(5.35*10^-6 C)/(1.30 m)^2

= 0.20513609467 N

The net electric force along x -axis is

Fx = F2 cos23 - F1 cos23

= 0

The net electric force along y-axis is

Fy = [F1 + F2] sin 23

= 2(0.20513609467 N) sin 23

= 0.160416426  N

The magnitude of net electric fore is

F =  0.160416426 N

Direction is f =tan-1[Fy/Fx]

= 90 degree

b) Given that mass of charge q1 is m = 1.10 x 10^-3 kg

The acceleration of the charge q1 is

a = F/m

= (0.160416426 N)/(1.60*10^-3 kg)

= 100.260266 m/s^2

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