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PLEASE HELP!! ALL THREE PARTS!!! Consider the RC circuit in the figure below. Th

ID: 2280288 • Letter: P

Question

PLEASE HELP!! ALL THREE PARTS!!!

Consider the RC circuit in the figure below. The switch was at position a for a long period of time and it is suddenly switched to position b at time t = 0.


PART A

What is Vc at time t = 2.00 ms?

Use the following data : R = 502.5 ?, C = 4.00 ?F, Vb = 3.05 V.

PART B

What is the total energy dissipated by the resistor R after the switch is thrown?

PART C

Using the same data as before, consider the case when the switch is in position b for a long time, and

then it is switched to position a at time t = 0. What is Vc at time t = 2.00 ms?

Consider the RC circuit in the figure below. The switch was at position a for a long period of time and it is suddenly switched to position b at time t = 0. What is Vc at time t = 2.00 ms? Use the following data : R = 502.5 ?, C = 4.00 ?F, Vb = 3.05 V. What is the total energy dissipated by the resistor R after the switch is thrown? Using the same data as before, consider the case when the switch is in position b for a long time, and then it is switched to position a at time t = 0. What is Vc at time t = 2.00 ms?

Explanation / Answer


equautin gfor charge while charging mechanism as

q = Q I(1-e^-t/RC)-------------------------------------1

where RC is called timeconstant and denoted by T

so T = RC

similarly we get current variation as

i = io(e^-t/Rc)--------------------------------------------2


we can get the eqns of charge and current while discharging as

q = Qe^-t/RC -------------------------------------------------3

i = io e^-t/RC----------------------------------------------4


we can get the eqvation for Voltage as

V = Vo(1-e^t/RC) while charging-------------------------------------5

V= voe^-t/RC while discharging-----------------------------------------6


these 6 set of equations are usually needed to solve problems in RC circuit


so lets solve your problem now


a. Vc = V0(1-e^-t/Rc)

Vc = 3.05*(1-e^-2*10^-3/(502.5*4*10^-6)

Vc = 1.922 volts


b. since switch is throen after along time, eenergy disspiated = eenrgy across resistor

so U = 0.5CV^2

U = 0.5 * 4*10^-6 * 3.05*3.05

U = 18.605 uJ


c, while discharging

Vc = 3.05*(e^-2*10^-3/(502.5*4*10^-6)

Vc =1.127 volts


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