An 8.5 kg object is moving in the positive direction of an x axis. When it passe

Question

An 8.5 kg object is moving in the positive direction of an x axis. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure below gives its kinetic energy K versus position x as it moves from x = 0 to x= 5.0 m; K0 = 32.0 J. The force continues to act. What is v when the object moves back through x = -3.0 m?
m/s

An 8.5 kg object is moving in the positive direction of an x axis. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure below gives its kinetic energy K versus position x as it moves from x = 0 to x= 5.0 m; K0 = 32.0 J. The force continues to act. What is v when the object moves back through x = -3.0 m?

Explanation / Answer

F=(K0-0)/(0-5) = -6.4 N

a = -6.4/8.5 = -0.753 m/s^2

v^=u^+2*as

s=5+3=8 m

v=sqrt(2*0.753*8)

v = -3.47 m/s

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