An 8.5 kg block of metal is suspended from a scale and immersed in water, as in

Question

An 8.5 kg block of metal is suspended from a scale and immersed in water, as in the figure below. The dimensions of the block are 12.0 cm multiplied by 9.5 cm multiplied by 9.5 cm. The 12.0 cm dimension is vertical, and the top of the block is 5.00 cm below the surface of the water.
(a) What are the forces exerted by the water on the top and bottom of the block? Take P0 = 1.0130 105 N/m2.
Ftop 914.28 Your answer is correct. N
Fbottom 929.27 2Your answer is correct. N

(b) What is the reading of the spring scale?

Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. N

Explanation / Answer

Net force on the block F = Weight - buoyant force

= m * g - (Fbottom   - Ftop)

= 8.5 * 9.8 - (929.27 - 914.28)

= 68.13 N

Hence reading of scale = F

= 68.13 N

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