A sequence of potential differences V is applied across a wire (diameter = 0.28

Question

A sequence of potential differences V is applied across a wire (diameter = 0.28mm , length = 11cm ) and the resulting currents I are measured as follows:

If this wire obeys Ohm's law, graphing I vs. V will result in a straight-line plot.

Part A

Based on this data, can you conclude that the wire obeys Ohm's law (i.e., is I vs. V plot a straight line with the expected y-intercept, within the values of the significant figures)?

I already answered this, and it is yes.

Part B

Determine the wire's resistance R.

Express your answer to two significant figures and include the appropriate units.

Part C

Calculate the wire's resistivity.

Express your answer to two significant figures and include the appropriate units.

*Please show all steps and answer with the correct significant figures and units.

Explanation / Answer

B. apply ohms law V = iR

so resistance R1 = V/i = 0.1/72 = 1.388 ohms

R2 = 0.2/142 = 1.408 ohms

R3 = 0.3/218 = 1.376 ohms

R4 = 0.4/290 = 1.379 ohms

R5 = 0.5/357 =1.40 ohms

Ravg = 1.388 + 1.408 + 1.376 +1.379 +1.40/5 = 1.392 ohms

C. resistance R = rho L/A

so resistivitiy rho = RA/L

rho = 1.392 * 3.14 * 0.14 *0.14 *10^-6/0.11)

rho = 7.77 *10^-7 ohm-m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.