Use the exact values you enter to make later calculations. Two capacitors are co

Question

Use the exact values you enter to make later calculations.

Two capacitors are connected in series. Using the same instruments as you did in the lab, you record both the capacitance of and the voltage difference across the electrodes of the capacitors individually. Complete the table below using theoretical formulae.

Capacitor #1 (Larger Capacitance) Capacitor #2 (Smaller Capacitance)

Total Arrangement (Theoretical) Voltage Difference (V) 3.530 6.500
Capacitance (µF) 1004.000 555.000 Charge (µC)

Energy (µJ)




I only need the total Charge and energy Use the exact values you enter to make later calculations. Two capacitors are connected in series. Using the same instruments as you did in the lab, you record both the capacitance of and the voltage difference across the electrodes of the capacitors individually. Complete the table below using theoretical formulae.

Explanation / Answer

Total Charge = CV (for total ) = 10.03*357.42=3584.9226

Total Energy = 1/2 * c *v^2 = 17978.386839

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