4. When a 24[?] resistor is connected across a \"12-Volt\" car battery, a curren

ID: 2275941 • Letter: 4

Question

4. When a 24[?] resistor is connected across a "12-Volt" car battery, a current of 0.48[A] flows ... rather than what was expected.

. . . a) What terminal Voltage would make that current? ... what voltage has been dropped inside the battery?

. . . b) What Resistance must be inside the battery? (evident from the reduced terminal voltage)

. . . c) presuming that the internal Resistance stays the same, how much current would flow thru a 6.0[?] resistor, connected across this battery?

5. A Power Supply provides 2.0[A] to the high (+) side of Resistor 1 ;

MORE INFO: The voltage across R1 is 10.4V, and the low side of R1 is connected to two resistors :

*) R2 is 64[?] which conducts 0.4[A] to the PowerSupply negative

*) R3 also conducts to the PS(?) Calculate :

. . . a) R1's Power . . . b) power supply voltage . . . c) R3's Resistance

a) I=.48

Vr=IR = (.48)*24 =11.52V

Voltage drop=12-11.52=.48V

b) Rin= Voltage drop / I = .48/.48 = 1ohm

c) I = V/(R+Rin) = 12/(6+1) = 1.7 A

5) V=IR1

10.4 = 2*R1

R1= 5.2ohm,

R1's power = V*I = (10.4)*(2) =20.8W

power supply voltage = 10.4 + (.4)*(64) = 36V

R3= V/I = (.4*64) / (2-.4) = 16ohm

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