Use the exact values you enter in previous answer(s) to make later calculation(s

Question

Use the exact values you enter in previous answer(s) to make later calculation(s). A car travels at 55 mi/h when the brakes are suddenly applied. Consider how the tires of a moving car come in contact with the road. When the car goes into a skid (with wheels locked up), the rubber of the tire is moving with respect to the road; otherwise, when the tires roll, normally the point where the tire contacts the road is stationary. Assume the coefficients of friction between the tires and the road are nK = 0.80 and = 0-90. Calculate the distance required to bring the car to a full stop when the car is skidding. Calculate the distance required to bring the car to a full stop when the wheels are not locked up. How much farther does the car go if the wheels lock into a skidding stop? Give your answer as a distance in meters and as a percent of the nonskid stopping distance. Can antilock brakes make a big difference in emergency stops? Explain. ( -Select- j) because the stopping distance with antilock brakes is [ -Select- $ ] the stopping distance without antilock brakes.

Explanation / Answer

55 mi/hr = 24.5 m/s
Kinetic energy of the car = force applied by friction

0.5 * m * 24.5 * 24.5 = 0.80 * m * 10 * distance
Thus distance = 37.51m

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