Does anyone have a clue how to solve this? A shift of one fringe in the Michelso

Question

Does anyone have a clue how to solve this?

A shift of one fringe in the Michelson-Morley experiment would result from a difference of one wavelength or a change of one period of vibration in the round-trip travel of the light when the interferometer is rotated by 90 degree . What speed would Michelson have computed for Earth's motion through the ether had the experiment seen a shift of one fringe? (The orbital speed of Earth is 29.8 km/s and the expected number of fringes in the Michelson-Morley experiment is 0.4.) km/s

Explanation / Answer

29.8/0.4=74.5 km/s

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