The drawing shows an electron entering the lower left side of a parallel plate c

Question

The drawing shows an electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of the electron is 6.30  

The drawing shows an electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of the electron is 6.30 times 106 m/s. The capacitor is 2.00 cm long, and its plates are separated by 0.150 cm. Assume that the electric field between the plates is uniform everywhere and find its magnitude.

Explanation / Answer

The initial horiz. vel. of the electron is unchanged (as force on e is vertical) .. so time between the plates is given by .. t = 2.0m / 6.3*10^6 m/s .. .. t = 3.174*-10^-7 s

Vertical accel. due to field force obtained from .. d(v) = ut +

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