Help! Last attempt!!! Two charges of q1 = 1.4 mu C and q2 = -2.1 mu C are d = 0.

Question

Help! Last attempt!!!

Two charges of q1 = 1.4 mu C and q2 = -2.1 mu C are d = 0.54 m apart at two vertices of an equilateral triangle as in the figure below. What is the electric potential due to the 1.4-mu C charge at the third vertex, point P? What is the electric potential due to the -2.1-mu C charge at P? Find the total electric potential at P. Your response differs from the correct answer by more than 100%. V What is the work required to move a 3.9-mu C charge from infinity to P? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. J

Explanation / Answer

a) V(potential) = k*q/r = 9*10^9* 1.4*10^-6/0.54 = 23333.33 V/c

b) V(potential) = k*q/r = 9*10^9* -2.1*10^-6/0.54 = -35000 V/c

c) V = 23333.33 - 35000 = -11666.67 V/c

d) W= q*V at P = -3.9 * -11666.67 = 45500 J

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