The drawings show three charges that have the same magnitude but may have differ
ID: 2270974 • Letter: T
Question
The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is |q|= 2.8 ?C, and the distance between them is d = 3.9 mm. Determine the magnitude of the net force on charge 2 for each of the three drawings.
Explanation / Answer
Magnitude of force between charge q1,q2 and q2,q3 = Kq^2/d^2= 9*10^9*2.8^2/(3.9^2*10^-6)=4.63*10^15 N. 2which we will call F.
Now,a) Force on q2 due to both q1 & q3 will be on left side with magnitude F each.
So net force 2F=9.26*10^15N.
B)Force on 2 due to 1 will be on right of magnitude F and on left due to 3 of magnitude F.
So they will cancel and net force=0.
C)forces will be perpendicular with same magnitude F.SO net force =2^0.5 F=6.56*10^15 N
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