Three charged particles are placed at each of three corners of an equilateral tr

Question

Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 2.8cm . Two of the particles have a negative charge: q1 = -7.3nC and q2 = -14.6nC . The remaining particle has a positive charge, q3 = 8.0nC . What is the net electric force acting on particle 3 due to particle 1 and particle 2?

Find the net force ?F? 3 acting on particle 3 due to the presence of the other two particles. Report you answer as a magnitude ?F3 and a direction ? measured from the positive x axis.

Explanation / Answer

let q3 be at origin.

q2 is on x axis and q1 in 1st quadrant.

F1 = 9 * 10^9 * 7.3 * 10^-9 * 8*10^-9 / 0.028^2 * (cos 60 i + sin60 j)

= 6.7 * 10^-4 (cos 60 i + sin60 j)

F2 = 9 * 10^9 * 14.6 * 10^-9 * 8*10^-9 / 0.028^2

= 13.4 *10^-4 i

F3 = F1 + F2

= 13.4 *10^-4 i + 6.7*10^-4 (cos 60 i + sin60 j)

= 1.675 *10^-3 i + 0.58 * 10^-3 j

hence

mag = 1.77 mN

direction = 19.1 degrees from positive x axis.

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