The drawing shown below represents part of the arrangement of blood vessels in t

Question

The drawing shown below represents part of the arrangement of blood vessels in the kidney. The arrangement includes 2 sets of resistance vessels(afferent and efferent arterioles(afferent artery and efferent artery) separated by a capillary bed, the glomerulus(glom).Note that the kidney glomerulus is an example of a fenestrated capillary, so fluid is filtered from the capillary (into Bowman's space)When the resistance of the efferent artery (downstream, to the right) is higher than the afferent(upstream, to the left).Use the diagram and values provided to answer parts a, b, c and d. J = K(p_cap - P_int) - sigma(pi_cap - pi_int) sigma = 1 for kidney capillaries; disregard K for the following calculations. P_glom = ??? __int = 1 mm Hg Product _glom = 12 mm Hg Product _int = 0 mm Hg a) Calculate P_glom. b) Calculate flux (J) through the glomerular capillary bed. Is there net filtration (fluid loss) or reabsorption (fluid uptake into the capillary) in this capillary bed? c)if the efferent arteriole is dilated, such that R_eff art = 0.001, what is the new value for P_glom? d) With R_eff art = 0 001 calculate the new flux (J) through the glomerular capillary bed. There net filtration or reabsorption in this capillary bed?

Explanation / Answer

a) Prenal art - Pglom = Raff art x Q ......(Equation 1, where Q is arteriole flux)

Pglom - Prenal vein = Reff art x Q.......(Equation 2)

Putting the Values,

63 - Pglom = 0.012 x Q........(1)

Pglom - 3 = 0.001 x Q........(2)

Dividing Equation (1) by (2)....

63 - Pglom / Pglom -3 = 0.012 / 0.001

Solving above equation , Pglom = 15 mm of Hg.

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